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Which among the following is used to reduce \mathrm{TiCl_{4} \; to\; Ti}?
 

Option: 1

C 


Option: 2

Al 


Option: 3

Mg 


Option: 4

\mathrm{H_{2}}


Answers (1)

best_answer

Titanium dioxide is reacted with chlorine to form titanium tetrachloride, which is then reacted with magnesium to remove the chlorine and leaves behind the pure metal. 

In Kroll's process for titanium, Mg is used as a reducing agent

\mathrm{TiCl}_4+2 \mathrm{Mg} \rightarrow 2 \mathrm{MgCl}_2+\mathrm{Ti}

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