Get Answers to all your Questions

header-bg qa

Answers (1)

CFSE in tetrahedral complexes -

CFSE = \left [-\frac{3}{5}\left ( No.\;of\;electron\;in\;e \right )+\frac{2}{5}\left ( No.\;of\;\acute{e}\;in\; t_{2}\right ) \right ] \bigtriangleup t

-CFSE in octahedral complex -

CFSE =\left [- \frac{2}{5}\left ( No. of\;electron\;in\;t_{2}g \right ) +\frac{3}{5}\left ( No. of\;\acute{e}s\;in\;eg \right ) \right ]\bigtriangleup \circ

 

Crystal Field Theory -

According to this theory, metal and ligand are considered as point charges. This theory deals with the electrostatic force of attraction means the talks about the ionic character of M-L bond. 

-

K_{3}\left [ CO\left ( CN \right )_{6}\right ] have CN- ligands which is strong-field ligand among the given ligand in other complexes.

  

Posted by

lovekush

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE