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 Which of the following arrangements represents the increasing  order (smallest to largest) of ionic radii of the given species

O^{2-},S^{2-},N^{3-}P^{3-}?

Option: 1

O^{2-}<N^{3-}<S^{2-}<P^{3-}


Option: 2

O^{2-}<P^{3-}<N^{3-}<S^{2-}


Option: 3

N^{3-}<O^{2-}<P^{3-}<S^{2-}


Option: 4

N^{3-}<S^{2-}<O^{2-}<P^{3-}


Answers (1)

best_answer

The size of noble gas configuration anions increases down the group because of greater orbits and decreases along with the period because of greater nuclear charge.

N^{3-}> O^{2-}\:and \:P^{3-}> S^{2-}

also, O^{2-}< S^{2-}

\therefore \:O^{2-}< N^{3-}< S^{2-}< P^{3-}

Posted by

SANGALDEEP SINGH

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