Get Answers to all your Questions

header-bg qa

Which of the following points is outside the circle x^2+y^2-6x+10y-10=0

Option: 1

(2,2)


Option: 2

(5,5)


Option: 3

(3,3)


Option: 4

All of the above


Answers (1)

best_answer

As we learnt

Position of a point w.r.t a circle 

If x_{1}^{2}+y_{1}^{2}+2gx_{1}+2fy_{1}+c> 0 . then the point is outside the circle.

 

Here,

For (2,2)

   S_1=4+4-12+20-10=6>0, so it lies outside the circle

For (5,5)

 S_1=25+25-30+50-10=60>0, so it lies outside the circle

For (3,3)

  S_1=9+9-18+30-10=20>0,  so it lies outside the circle

Hence (D) is the correct option

Posted by

Deependra Verma

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions