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Which of the molecules has larger the bond length of $O-O$ :
Option: 1
$K\! O_{2}$

Option: 2
$O_{2}\left [ AsF_{6} \right ]$

Option: 3
$O_{2}$

Option: 4
$Na_{2}O_{2}$

Answers (1)

best_answer

As we have learnt,

$K\! O_{2}$ has $O_2^-$ (super oxide ion), Bond Order = $1.5$
$O_{2}\left [ AsF_{6} \right ]$ has $O_2^{+}$ , Bond Order = $2.5$
$O_{2}$ , Bond Order = $2$
$Na_{2}O_{2}$ has $O_{2}^{2-}$ (peroxide ion), Bond Order = $1$ .

Higher is the Bond Order, smaller is the bond length.

1 < other given values of Bond Order.

$Na_{2}O_{2}$ has $O_{2}^{2-}$ , low bond order than others.

Hence $Na_{2}O_{2}$ will have a larger bond length of $O-O$ .

Hence, option number (4) is correct.

Posted by

Divya Prakash Singh

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