Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

Which of the molecules has larger the bond length of $O-O$ :
Option: 1
$K\! O_{2}$

Option: 2
$O_{2}\left [ AsF_{6} \right ]$

Option: 3
$O_{2}$

Option: 4
$Na_{2}O_{2}$

Answers (1)

best_answer

As we have learnt,

$K\! O_{2}$ has $O_2^-$ (super oxide ion), Bond Order = $1.5$
$O_{2}\left [ AsF_{6} \right ]$ has $O_2^{+}$ , Bond Order = $2.5$
$O_{2}$ , Bond Order = $2$
$Na_{2}O_{2}$ has $O_{2}^{2-}$ (peroxide ion), Bond Order = $1$ .

Higher is the Bond Order, smaller is the bond length.

1 < other given values of Bond Order.

$Na_{2}O_{2}$ has $O_{2}^{2-}$ , low bond order than others.

Hence $Na_{2}O_{2}$ will have a larger bond length of $O-O$ .

Hence, option number (4) is correct.

Posted by

Divya Prakash Singh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

0.1 M acetic acid solution having pH =3 is titrated against 0.05 M NaOH solution. Calculate pH at 1/4th stage of neutralization of acid.Option: 1

0.25×60+0.10x=0.15×(60+x)

Trending Articles/News

anam-khan

JEE Main 2026 session 2 application correction begins on jeemain.nta.nic.in; edit details by tomorrow

anam-khan

JEE Main 2026 Registration LIVE: Session 2 exam from April 2 to 9; shift timings, admit card, exam pattern

anam-khan

JEE Main 2026 session 2 registration ends today for BTech, BArch; apply at jeemain.nta.nic.in

Latest Question