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Which one of the following 0.06 \mathrm{M} aqueous solutions has lowest freezing point?
Option: 1 \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}
Option: 2 \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}
Option: 3 \mathrm{KI}
Option: 4 \mathrm{K}_{2} \mathrm{SO}_{4}

Answers (1)

best_answer

As we have learnt ,

\mathrm{\Delta T_{f}=i \cdot K _{f} \cdot m}

For equimolar solutions, the freezing point decreases as the van't Hoff factor increases.

Since, \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}  forms the greatest number of ions in solution, it has the greatest van't Hoff factor and as a result, has the lowest freezing point.

Hence, the correct answer is Option (1)

Posted by

sudhir.kumar

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