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Which one of the following gives the value of magnetic field due to small current element according to, Biovt-Savart's law

Option: 1

\frac{i\Delta lsin\Theta }{\gamma ^{2}}


Option: 2

\frac{\mu o}{4\pi}\cdot \frac{i\Delta lsin\Theta }{r}


Option: 3

\frac{\mu o}{4\pi}\cdot \frac{i\Delta lsin\Theta }{r^{2}}


Option: 4

\frac{\mu o}{4\pi}\cdot \frac{i\Delta lsin\Theta }{\gamma ^{3}}


Answers (1)

best_answer

As we learned

Biot-Savart's Law -

Determine the magnetic feild at any point due to current carrying conductor. 

- wherein

For infinitesimally small conductor. 

 

 Accordibg to Biot-Savart's law

 

 dB \propto I

dB \propto dl or \Delta l

dB \propto sin\Theta

dB \propto \frac{1}{\gamma ^{2}} \Rightarrow dB =\frac{\mu o}{4\pi }\frac{idlsin\Theta }{\gamma ^{2}}

Posted by

manish painkra

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