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why does the induced emf change in a circular loop and not in a rectangular loop when it moves out of a uniform magnetic field region?

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We know that the induced EMF (\epsilon) is given by:

\epsilon = -N\frac{d\phi}{dt}

Where,  \phi = B.A, since we started off with B constant
Then,

\frac{d\phi}{dt}\propto \frac{dA}{dt}

Now,

In the case of the rectangular loop, the amount by which the surface changes as the loop moves out, is constant, 

Therefore,

\frac{dA_{rec.}}{dt} = constant \Rightarrow \epsilon = constant

Whereas in case of circluar loop, the change of magnetic flux isn't constant since the surface of the circle doesn't change by equal amounts as the loop moves out:

\frac{dA_{circle}}{dt} \neq constant \Rightarrow \epsilon \neq constant

Posted by

Gautam harsolia

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