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An alloy contains the copper and aluminum in the ratio 7:4. While making the weapons from this alloy, 12% of the alloy get destroyed. If there are 12 kg of aluminum in the weapon, then the weight of the alloy required is :

Option 1)
45kg
Option 2)
40kg
Option 3)
37.5 kg
Option 4)
14.4 kg
Option 5)
48 kg

Answers (1)

best_answer

Copper : Aluminum = 7 : 4

$\left ( \frac{88}{100} \right )\times \left ( \frac{4x}{11} \right )=12$

$x=37.5\, Kg$

Posted by

rishi.raj

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