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Find the greatest number of four digits which when divided by 10, 11, 15, and 22 leaves 3, 4, 8 and 15 as remainders respectively.

Option 1)

$9907$

Option 2)

$9902$

Option 3)

$9903$

Option 4)

9100

Option 5)

$None\: of\: these$

Answers (1)

best_answer

LCM of 10, 11, 15, 22 = 330

largest 4-digit number = 9999

Remainder when 9999/330 = 9900

to make it divisible by 330

9900-7 => 9893

Posted by

rishi.raj

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