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What is the last remainder when 223 is successively divided by 4, 5 and 6?

Option 1)

$5$

Option 2)

$0$

Option 3)

$6$

Option 4)

$1$

Option 5)

$3$

Answers (1)

best_answer

The last remainder when 223 is successively divided by 4, 5 and 6 is:

$\begin{matrix} 4 & 223 & \\ 5 & 55&3 \\ 6&11 &0 \\ & 1& 5 \end{matrix}$

$Remainder= 5$

Posted by

rishi.raj

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