If x = -0.5, then which of the following has the smallest value?
$2^{1 / x}$
$1 / x$
$1 / x^2$
$2^x$
$1 / \sqrt{-x}$
X= 0.5
As 1/x2 and 2xx= will be +ve
1/x= -1/0.5= -2
21/x=2=1/4=.15
1/.51/x=+ve, so 1/x is least
Option B
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