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  •  A is twice old as B. Five years ago A was 3 times as old as B. Find their present ages.

 A is twice old as B. Five years ago A was 3 times as old as B. Find their present ages.

Answers (1)

best_answer

Let B’s age = x. Then, A’s age = 2 x.

Five years ago- A’s age = 2 x − 5 and B’s age = x − 5 

Given- $$
2x−5=3(x−5)
$$

Solving the equation- $$
2x−5=3x−15
$$ $$
x=10
$$

So, the present age is 

  • A = 2x = 20 years
  • B = x = 10 years
Posted by

Saniya Khatri

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