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Get Answers to all your Questions
A is twice old as B. Five years ago A was 3 times as old as B. Find their present ages.
Answers (1)
Let B’s age = x. Then, A’s age = 2 x.
Five years ago- A’s age = 2 x − 5 and B’s age = x − 5
Given- $$
2x−5=3(x−5)
$$
Solving the equation- $$
2x−5=3x−15
$$ $$
x=10
$$
So, the present age is
- A = 2x = 20 years
- B = x = 10 years
View full answer
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