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Get Answers to all your Questions
- #Law
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- #Common Admission Test
The distance between two stations A and B is 440 km. A train starts at 4 p.m. from A and move towards B at an average speed of 40 km/hr. Another train starts B at 5 p.m. and moves towards A at an average speed of 60 km/hr. How far from A will the two trains meet and at what time?
Option: 1
200,8 p.m.
Option: 2
300,9 p.m.
Option: 3
200,9 p.m.
Option: 4
300,8 p.m.
Answers (1)
The sum of the distances covered by both trains should be equal to the total distance between the stations A and B: 40t+60(t−1)=44040t + 60(t - 1) = 44040t+60(t−1)=440
40t+60t−60=440
100t−60=440
100t=500
t=5
So, the trains will meet 5 hours after Train A starts from A.
Train A starts at 4 p.m. so 5 hours from 4 p.m. is 4 p.m. + 5 hours = 9 p.m.
The two trains will meet 200 km from A at 9 p.m.
Option 3: 200, 9 p.m.
View full answer
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