Directions for question:
In 1985, seven infamous gangsters – Mr Ameen, Mr Bilal, Mr Cheena, Mr Davar, Mr Elias, Mr Fayaz and Mr Gawli – all of them chiefs of their respective underworld gangs, were candidates in the election for the position of the Head of all the underworld gangs in the business of extortion and gambling in Mumbai.
The election was conducted in three rounds. In the first round, each of the chiefs of all the underworld gangs in the business of extortion and gambling in Mumbai cast three votes for three different candidates. The two candidates with the least votes were eliminated. In the second round, each of the chiefs eligible to cast a vote cast two votes for two different candidates. The two candidates with the least votes were again eliminated. In the third round, each of the chiefs eligible to cast a vote cast one vote for any one candidate.
A candidate in the election for the position of the Head of all the underworld gangs in the business of extortion and gambling in Mumbai, who was taking part in a given round, was not eligible to vote in that round. But once eliminated he became eligible to vote in the next rounds. All the other chiefs who were not candidates in the election were eligible to vote in all the rounds. In each of the three rounds, there were no absentees, and all the chiefs who were eligible for a particular round cast their votes.
In the first round a total of 129 votes were cast in all, and the top three candidates were Mr Bilal with 25 votes, Mr Gawli with 20 votes and Mr Ameen with 18 votes. In the second round, Mr Cheena received 8 votes more than he did in the first round, Mr Bilal was 3 votes behind Mr Cheena in the second place, and Mr Elias was in the third place with 15 votes. In the third round, Mr Cheena received the same number of votes he did in the first round and ended up winning the election. Mr Bilal finished last in the third round.
Question:
How many of the chiefs of all the underworld gangs in the business of extortion and gambling in Mumbai voted in the third round of the election ?
43
45
47
49
Number of votes cast in the first round = 129/3 = 43
Two candidates with the least votes were eliminated in the first round.
Thus, number of voters in the second round = 43+2 = 45
Two candidates with the least votes were eliminated in the second round.
Number of voters in the third round = 45+2 = 47
In the third round, votes cast per voter = 1
So number of votes cast in the third round = 47*1 = 47