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If $f(x)=\frac{5x-3}{2x+1}$ . Find the inverse of f(x)
Option: 1
$\frac{x+3}{2x-5}; x\neq5/2$

Option: 2
$\frac{-(x+3)}{2x-5}; x\neq5/2$

Option: 3
$\frac{(x+3)}{2x-5}; x\neq5/2$

Option: 4
$\frac{(x-3)}{2x-5}; x\neq5/2$

Answers (1)

best_answer

$y=\frac{5x-3}{2x+1}$

$\\y(2x+1)={5x-3}\\\\2xy + y =5x - 3\\\\2xy - 5x =- 3-y\\\\x (2y-5)= -(3+y)\\\\x = \frac{-(3+y)}{2y-5}$

Now we can say inverse is equal to

$y= \frac{-(x+3)}{2x-5}$

Posted by

Pankaj Sanodiya

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