In the adjoining figure, ∠ DAB = 60°, ∠ ABD = 90°, then ∠ ACB = .
90°
45°
30°
60°
∠ ACB = ∠ ADB = 60° (angle in the same segment of a circle)
In triangle ADB
∠ ADB + ∠ DAB + ∠ ABD = 180°
∠ ADB + 60° + 90° = 180°
∠ ADB = 30°
Since
∠ ACB = ∠ ADB = 30° (angle in the same segment of a circle)