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  • Let O is the circumcentre of triangle ABC with circumradius 13 cm. Let BC = 24 cm and OD is perpendicular to BC. Then the length of OD is  Option:

Let O is the circumcentre of triangle ABC with circumradius 13 cm. Let BC = 24 cm and OD is perpendicular to BC. Then the length of OD is

 

Option: 1

7 cm


Option: 2

3 cm


Option: 3

4 cm


Option: 4

5 cm


Answers (1)

best_answer

The point of intersection of the perpendicular bisectors of the sides of a triangle is called its circumcenter. The circumcenter is equidistant from all the vertices of the triangle. 

Given that, circumradius = OB = 13 cm

BC = 24 cm

and, BD = DC = 12 cm

we need to find OD

Triangle BOD is right-angle triangle, with a right angle at D

Apply Pythagoras theorem, we get

OD=\sqrt{13^2-12^2}=5\;cm

 

Posted by

Shailly goel

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