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The quadratic polynomial whose zeros are 1 and -3 is

Option: 1

x^2+2x-3


Option: 2

x^2-3x+2


Option: 3

x^2+x+3


Option: 4

x^2+3x-2


Answers (1)

best_answer

Let \alpha=1 and \beta=-3

Sum of zeros =(\alpha+\beta)=1+(-3)=-2

Product of zeros =\alpha \beta=1 \times(-3)=-3

So, the required polynomial is

\begin{aligned} x^{2}-(\alpha+\beta) x+\alpha \beta &=x^{2}-(-2) x+(-3) \\ &=x^{2}+2 x-3 \end{aligned}

Posted by

Gautam harsolia

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