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  • Two chords AB and CD of a circle intersect each other at P outside the circle. If AB = 6 cm, BP =2 cm, and PD =2.5 cm. Then CD is <img alt="" src="https://cdn.entrance360.com/media/u

Two chords AB and CD of a circle intersect each other at P outside the circle. If AB = 6 cm, BP =2 cm, and PD =2.5 cm. Then CD is

Option: 1

2.5 cm


Option: 2

3.9 cm


Option: 3

4.2 cm


Option: 4

5.6 cm


Answers (1)

best_answer

\begin{array}{l} A P \times B P=C P \times D P \\ \Rightarrow 8 \times 2=(C D+2.5) \times 2.5 \\ \Rightarrow C D=3.9 \mathrm{~cm} . \end{array}

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Anam Khan

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