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  • 1.4 g of an organic compound was digested according to Kjeldahl's method and the ammonia evolved was absorbed in 60 mL of M/10 H2SO4 solution. The excess sulphuric acid re

1.4 g of an organic compound was digested according to Kjeldahl's method and the ammonia evolved was absorbed in 60 mL of M/10 H2SO4 solution. The excess sulphuric acid required 20 mL of M/10 NaOH solution for neutralization. The percentage of nitrogen in the compound is:

Option: 1

3


Option: 2

5


Option: 3

10


Option: 4

24


Answers (1)

best_answer

As we have learnt,

In Kjeldahl method, we have

%N=1.4NV/W

Now, the given weight of organic compound = 1.4 gram

NH3 = Meq of H2SO4

Therefore, H2SO4 =(1×60) / 10
                          = 6 milimoles

Now, Meq of H2SO4 i.e reacted with NaOH = (20 x 1) / 20
                                                               = 1 millimole        

Therefore H2SO4 used against ammonia = 6-1
                                                            = 5 millimoles

% of N = (0.07 x 100) / 14
           = 5%
Therefore, Option(2) is correct

Posted by

vinayak

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