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  • 1.47 litre of a gas is collected over water at and 744 mm of H

1.47 litre of a gas is collected over water at \small 30^{\circ}C and 744 mm of Hg. If the gas weighs 1.98g and vapour pressure of water at \small 30^{\circ}C is 32 mm, what is the molar mass (in g/mol) of gas?

Option: 1

36


Option: 2

43.6


Option: 3

357.7


Option: 4

23.5


Answers (1)

best_answer

We have:
Given weight of gas = 1.98g
Volume of gas = 1.47L
Total pressure of gas given = 744mm and vapour pressure of water = 32mm
Thus, pressure of gas = 744 - 32 = 712 mm or 712/760 atm
Now, according to ideal gas equation, we have:
pV = nRT

\therefore n=\frac{\frac{712}{760}\times 1.47}{0.0821 \times 303}=0.055 moles
Thus, molar mass of gas = 1.98/0.055 = 36g/mol
 

Posted by

manish

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