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20 ml of 1 M \mathrm{Ce^{4+}} solution is required to convert 10 ml of 1M of \mathrm{Sn^{2+}} solution to \mathrm{Sn^{4+}}. What is the oxidation state of Cerium in product?

Option: 1

+1


Option: 2

+2


Option: 3

+3


Option: 4

+5


Answers (1)

best_answer

The reaction is \mathrm{\mathrm{Ce}^{4+}+\mathrm{Sn}^{2+} \rightarrow \mathrm{Sn}^{4+}+\mathrm{Ce}^{n+}}

To convert 1 mol \mathrm{Sn^{2+}} to 1 mol of \mathrm{Sn^{4+}} double amount of \mathrm{Ce^{4+}}  is required and hence the product must have +3 oxidation state.

Posted by

manish painkra

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