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  • A 100 ml mixture containing 72% of by volume and the rest an unknown gas X was kept

A 100 ml mixture containing 72% of \small CH_4 by volume and the rest an unknown gas X was kept in a vessel. Due to a very fine crack, the mixture effused out. 21 ml of the mixture was lost and the remaining mixture contained 68.35% of methane by volume. Calculate the molar mass of gas X. All the measurements are made at the same temperature and pressure.

Option: 1

85.4


Option: 2

87.1


Option: 3

77.3


Option: 4

94.2


Answers (1)

best_answer

We have initial volume of mixture = 100ml

Thus, the mixture has 72ml of  CH_4 and 28ml of X.
Thus, we have:

\frac{P_{CH_4}}{P_X}=\frac{72}{28}

After the crack, the volume left = 100-21 = 79ml
Thus, the volume of CH_4 left after crack =(79\times 68.35)/100=54ml
Thus diffused volume of  CH_4=72-54=10mlAnd diffused volume of X=21-18=3ml
Now, we know that:

\frac{V_{CH_4}}{V_X}=\sqrt{\frac{M_X}{M_{CH_4}}}\times\frac{72}{28}

Thus, M_X=87.1

 

 

Posted by

rishi.raj

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