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A block of mass 1 \mathrm{kg} is placed over a frictionless bar as shown in the figure. Initially, the block was at rest, and spring was in its natural length. If a horizontal bar starts rotating about a vertical axis about its one end with constant angular velocity of 10 \mathrm\ {rad} / \mathrm{s}. Then the required spring constant to keep the block in equilibrium:

Option: 1

10\ N/m


Option: 2

100\ N/m


Option: 3

5\ N/m


Option: 4

50\ N/m


Answers (1)

best_answer

In case of equilibrium,

F_{\text {net }}=0 \\ m a=k x \\ m\omega^{2}x=kx \\ k=m\omega^2\\ k=(1)(10)^2\\ k=10\ N/m

 

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rishi.raj

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