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  • A body moved down a 45° inclined plane, here it takes twice the time to roll down than in comparison to the time taken to cover a similar distance without friction.  What will be

A body moved down a 45° inclined plane, here it takes twice the time to roll down than in comparison to the time taken to cover a similar distance without friction.  What will be the coefficient between the body and the plane?

 

Option: 1

0.85


Option: 2

0.75


Option: 3

0.66


Option: 4

0.48


 


Answers (1)

best_answer

 if there is a presence of friction then coefficient  =\ g(sin\theta\ -\ \mu\ cos\theta)

∴ Time taken by the ball to slide down the plain 

In absence of friction

t1\ =\frac{\sqrt{2s}}{a}\

 

In presence of friction

t_2=\frac{\sqrt{2s}}{g(sin\theta\ -\ \mu\ cos\theta)}

 

t_2 = 2t_1

\therefore\ {t^2}_2\ =\ {4t^2}_1

Or else

2s/g\ (sin\theta\ -\ \mu\ cos\theta)=\ 2s\times4/g\ \ sin\theta

sin\theta\ =\ 4\ sin\theta\ -\ \ 4\mu\ cos\theta

\mu\ =3/4\ \ tan\theta\ =3/4\ \ =\ 0.75

Posted by

shivangi.bhatnagar

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