A bulb of three litre capacity filled with air is heated from to
. The air thus expelled measured 1.45L at
. Considering the pressure to be 1 atm throughout the experiment and ignoring the expansion of bulb, calculate temprature (in oC).
327
320
350
335
We have:
Initial volume of bulb = 3L
Initial temperature = 273 + 27 = 300K
Final temperature = 273 + t
Thus, according to charles’ law, we have:
Now at , the volume of gas is 1.45L, thus, we have:
...............................(i)
Now the gas is heated from to
, thus volume can be given as follows:
Using equation (i) we have:
Thus,