# A capillary of radius r is immersed in water and water rises in it to height h. The mass of the water in the capillary is 5 g. Another capillary tube of radius 2r us immersed in water. The mass of water that will rise in this tube is: Option: 1  2,5 g Option: 2 5.0 g Option: 3  10. g   Option: 4 20.0 g

Mass of water in the capillary tube = $m=\rho Ah$

and using

$h=\frac{2T\cos \Theta }{\rho gr}$

we get

$m=\rho Ah=\rho *(\pi r^2)*\frac{2T\cos \Theta }{\rho gr}\\ \Rightarrow m \ \alpha \ r$

So $\frac{m_2}{m_1}=\frac{r_2}{r_1}=\frac{2r}{r}=2\\\\ m_2=2\times m_1=2\times 5=10 \ g$

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