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A conducting rod PQ is moving in constant magnetic field B with velocity V . Resistance of PQ is R the magnetic force experience by rod is 

Option: 1

\frac{B^2vl}{R}


Option: 2

\frac{Bvl}{R}


Option: 3

\frac{B^2vl^2}{R^2}


Option: 4

\frac{B^2vl^2}{R}


Answers (1)

As we have learned

Magnetic force -

F=Ilb=B\left ( \frac{Blv}{R} \right )l

F=\frac{B^{2}vl^{2}}{R}

 

 

- wherein

B\rightarrow Magnetic field

R\rightarrow Resistance

V\rightarrow Velocity

 

 Conductor PQ experience a magnetic force in opposite direction of its motion 

F_m= Bil .......(1)

induced emf , |\varepsilon |= \left | -\frac{d\phi }{dt} \right | = Bvl

induced current , i = \frac{\varepsilon }{R}= \frac{Bvl }{R}

Putting i in equation (1)

           F_m = B\left ( \frac{Bvl}{R} \right )l

F_m = \left ( \frac{B^2vl^2}{R} \right )

 

 

 

 

 

Posted by

Ramraj Saini

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