Q.9) A container has two chambers of volumes $V_1=2$ litres and $V_2=3$ litres separated by a partition made of a thermal insulator. The chambers contains $n_l=5$ and $n_2=4$ moles of ideal gas at pressures $p_1=1 \mathrm{~atm}$ and $p_2=2 \mathrm{~atm}$, respectively. When the partition is removed, the mixture attains an equilibrium pressure of :
A) 1.8 atm
B) 1.3 atm
C) 1.6 atm
D) 1.4 atm
Solution:
Use the ideal gas law: $p V=n R T$. Since temperature and R are constant, use $p_1 V_1+p_2 V_2=P\left(V_1+\right.$ $V_2$ ).
Substitute:
$$
\begin{aligned}
& 1 \times 2+2 \times 3=P \times(2+3) \\
& 2+6=5 P \Rightarrow 8=5 P \Rightarrow P=8 / 5=1.6 \mathrm{~atm}
\end{aligned}
$$
Hence, the answer is option (3) 1.6 atm .