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  • A current source sends a current . When connected across an unknown load giv

A current source sends a current i=i_{0}\cos(\omega t). When connected across an unknown load gives a voltage output of, v=v_{0}\sin(\omega t + \frac{\pi}{4}) across that load. Then voltage across the current source may be brought in phase with the current through it by:

Option: 1

connecting an inductor in series with the load                                 
           


Option: 2

connecting a capacitor in series with the load          


Option: 3

connecting an inductor in parallel with the load

          


Option: 4

  connecting a capacitor in parallel with the load.


Answers (1)

best_answer

Given as -

v=v_{0} \sin \left ( \omega t+\pi /4 \right )=v_{0} \cos \left ( \omega t-\pi /4 \right )

and i=i_{0}\cos(\omega t)

So we can say i is leading v by 45^0

So to bring v in phases with i we will connect an inductor in series with the load.

since in an inductor, i lags v  

 

Posted by

Suraj Bhandari

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