A cylinder with a volume of 20-liter contains a gas with 6 atm pressure at . What would be the pressure (in atm) of the gas if it is heated to
?
7
8
5
6
We have,
= 27 + 273 = 300K,
= 77 + 273 = 350K
= 6atm
Thus, according to Gay-Lussac’s law, we have: