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  • A cylinder with a volume of 20-liter contains a gas with 6 atm pressure at <img alt="\small 27^{\circ}C" src="http://entrancecorner.oncodecogs.com/gif.latex?%5Cdpi%7B100%7D%20%5Csmall%2027%5E%7B%5C

A cylinder with a volume of 20-liter contains a gas with 6 atm pressure at \small 27^{\circ}C. What would be the pressure (in atm) of the gas if it is heated to \small 77^{\circ}C?

Option: 1

7


Option: 2

8


Option: 3

5


Option: 4

6


Answers (1)

best_answer

We have,
T_1 = 27 + 273 = 300K, T_2 = 77 + 273 = 350K
P_1 = 6atm

Thus, according to Gay-Lussac’s law, we have:

\\\mathrm{\frac{P_{1}}{T_{1}} =\frac{P_{2}}{T_{2}}}\\\\\mathrm{Thus,\, P_{2}=\frac{6\, x\, 350}{300}\: =\: 7atm}

 

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vinayak

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