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  • A lift of mass m is moving in upward direction with acceleration g/4 , its dispalcement is 'h' . Find out work (in mgh) done by tension force Option

A lift of mass m is moving in upward direction with acceleration g/4 , its dispalcement is 'h' . Find out work (in mgh) done by tension force 

Option: 1

0.25


Option: 2

1.25


Option: 3

2


Option: 4

0.75


Answers (1)

best_answer

As we have learned

Definition of work by constant force -

W=FS\cos \Theta

- wherein

The product of  magnitude of force \left ( F \right ) magnitude of displacement \left (S \right ) and cosine of the angle between them  \left (\Theta \right )

 

 

T - mg = m (g/4)

T = 5/4 mg 

W = FS \cos \theta

 W = [ 5/4 mg ] h \cos \theta

 W = 5/4 mgh 

 

 

 

 

 

Posted by

rishi.raj

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