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  • A man of 130 pounds was made to stand against the inner wall of a hollow cylinder and the rotor of the unknown radius is rotating at its vertical axis with a speed of 2.5rads-1, and the c

A man of 130 pounds was made to stand against the inner wall of a hollow cylinder and the rotor of the unknown radius is rotating at its vertical axis with a speed of 2.5rads-1, and the coefficient of friction between the wall and his clothing be 0.31. So what will be the radius of the rotor?

Option: 1

5m

 


Option: 2

6m


Option: 3

11m

 


Option: 4

3m


Answers (1)

best_answer

As we know to calculate the minimum angular speed of the rotation \omega=\sqrt{\frac{g}{\mu R}}

\omega=2.5rad^{-1}

g=9.8m/s^2

R\ =\ ?

\mu\ =\ 0.31

R=\frac{g}{\omega^2}\mu

R=\frac{9.8}{\left(2.5\right)^2}0.31

R=\frac{9.8}{1.93}

 R = 5m

 

 

Posted by

Pankaj

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