Get Answers to all your Questions

header-bg qa

A man of mass m stands at one end of a plank of length ‘L’ which lies at rest on a frictionless surface. The man walks to the other end of the plank. If the mass of plank is \frac{m}{3}, the distance that the man moves relative to the ground is

Option: 1

\frac{3L}{4}


Option: 2

\frac{L}{4}


Option: 3

\frac{4L}{5}

 


Option: 4

\frac{L}{3}


Answers (1)

best_answer

Answer (2)

Centre of mass of system will not move.

Distance moved by the plank =\frac{3L}{4}

Distance moved by man relative to ground =L-\frac{3L}{4}=\frac{L}{4}

Posted by

manish painkra

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks