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  • A metallic rod of mass per unit length 0.5 kg/m is lying horizontally on a smooth inclined plane which makes an angle of 30° with the horizontal. The rod is not allowed to slide down by flowing

A metallic rod of mass per unit length 0.5 kg/m is lying horizontally on a smooth inclined plane which makes an angle of 30° with the horizontal. The rod is not allowed to slide down by flowing a current through it when a magnetic field of induction 0.25 T is acting on it vertical direction. The current flowing in the rod to keep it stationary is - 

Option: 1

7.14A


Option: 2

5.98A


Option: 3

11.32A


Option: 4

14.76A


Answers (1)

best_answer

From figure for equilibrium, 

\begin{aligned} & m g \sin 30^{\circ}=\frac{I}{B} \cos 30^{\circ} \\ & \Rightarrow I=\frac{m g}{l B} \tan 30^{\circ} \\ &=\frac{0.5 \times 9.8}{0.25 \times \sqrt{3}}=11.32 \mathrm{~A} . \end{aligned}

 

Posted by

Anam Khan

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