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A network of inductances, each of value 1H, is shown in figure. The equivalent inductance of the circuit between points A and B is

Option: 1

6.218 H


Option: 2

0.268 H


Option: 3

8.162 H


Option: 4

2.618 H


Answers (1)

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1 and 2 in series in parallel with 3. The result of this is in series with 4, which is in parallel with 5, again in series with 6, which again is in parallel with 7, in series with 8 and in parallel with 9. Finally result of above steps, 10 & 11 are in series to get 2.618 H.

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Devendra Khairwa

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