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A non-viscous liquid of constant density 103 \mathrm{~kg} / \mathrm{m} 3 flows in streamline motion along a vertical tube P Q of variable cross-section. Height of P and Q are 2 \mathrm{~m} and 2.5 \mathrm{~m} respectively. Area of tube at Q is equal to 3 times the area of tube at P. Find the work done per unit volume by pressure as liquid flows from P to Q. Speed of liquid at P is 3 \mathrm{~m} / \mathrm{s}(\mathrm{g}=10 \mathrm{~m} / \mathrm{s} 2)

Option: 1

\mathrm{2000 \mathrm{~J} / \mathrm{m}^3}


Option: 2

\mathrm{1000 \mathrm{~J} / \mathrm{m}^3}


Option: 3

\mathrm{1575 \mathrm{~J} / \mathrm{m}^3}


Option: 4

\mathrm{900 \mathrm{~J} / \mathrm{m}^3}


Answers (1)

best_answer

\mathrm{ P+\rho g h+\frac{1}{2} \rho v^2=\text { cont } }

Need to find \mathrm{\Delta P}

\mathrm{ \rho g \Delta h+\frac{1}{2} \rho\left(v_p^2-v_a^2\right) }

Posted by

Kuldeep Maurya

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