Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • A particle of unit mass undergoes one-dimensional motion such that its velocity varies according

A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v=\beta x^{-2n} where b and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by

Answers (1)

best_answer

@Vishal gond 

as v=\beta x^{-2n}

use a=\frac{dv}{dt}=\frac{dv}{dx}*\frac{dx}{dt}=\frac{dv}{dx}*v

and  \frac{dv}{dx}=-2n*\beta x^{-2n-1}

so a=-2n*\beta x^{-2n-1}*\beta x^{-2n}=-2n\beta ^2 x^{-4n-1}

Posted by

avinash.dongre

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

Telangana NEET UG 2025 merit list out; 43,400 qualify for MBBS, BDS counselling
anam-khan

NEET Re-Exam 2025: 'Sympathy for students, but bad luck happens', HC reserves verdict on plea
anam-khan

NMC approves all 34 Telangana government medical colleges for 2025–26 academic year

Latest Question