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  • A reverse osmosis plant is designed to produce <img alt="10 \ \text{m}^3/\text{day}" src="https://entrancecorner.oncodecogs.com/gif.latex?10%20%5C%20%5Ctext%7Bm%7D%5E3/%5Ctext%7Bday%7D" /

A reverse osmosis plant is designed to produce 10 \ \text{m}^3/\text{day} of drinking water from seawater containing 35,000 ppm of dissolved salts. The membrane has a rejection coefficient of 0.98 for salt, and the applied pressure is 20 bar. What is the concentration of dissolved salts in the permeate?

Option: 1

 700 ppm 


Option: 2

1,400 ppm


Option: 3

 2,100 ppm

 


Option: 4

 2,800 ppm


Answers (1)

best_answer

The permeate flow rate can be calculated using the water recovery rate, which is defined as the ratio of the permeate flow rate to the feed flow rate: \text{Water recovery rate }= \frac{\text{Permeate flow rate}}{\text{Feed flow rate}} \times 100%

Given, 

\\\text{feed flow rate} = 10 \ \text{m}^3/\text{day}, \\ \text{salt concentration in feed }= 35,000 \text{ ppm}, \\ \text{rejection coefficient }= 0.98, \\ \text{and applied pressure = 20 bar.}

We can calculate the permeate flow rate as:

\text{Permeate flow rate} = \text{Feed flow rate} \times \text{Water recovery rate}

= 10 \times \frac{1 - \text{Rejection coefficient}}{\text{Applied pressure}}

= 0.1 \ \text{m}^3/\text{h}

Using the rejection coefficient, we can calculate the concentration of salts in the permeate as:

\\\mathrm{C_\text{permeate} = C_\text{feed} \times (1 - \text{Rejection coefficient})}\\\\ \mathrm{C_\text{permeate} = 35,000 \times (1 - 0.98) = 700 \ \text{ppm}}

Posted by

manish

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