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  • A short electric dipole has a dipole moment of &nb

A short electric dipole has a dipole moment of 16\times 10^{-9} \mathrm{Cm} The electric potential due to the dipole at a point at a diatnce of 0.6 m from the centre of the dipole, situated on the line making an angle of 60^{\circ} with the dipole axis is: 

\left(\frac{1}{4\pi\varepsilon_0} = 9\times10^{9}\mathrm{Nm^2/C^2} \right )

Option: 1

50 V


Option: 2

200 V


Option: 3

400 V


Option: 4

zero


Answers (1)

best_answer

\begin{aligned} V=\frac{K P \cos \theta}{r^{2}} &=\frac{1}{4 \pi \epsilon_{0}} \times \frac{P \cos \theta}{r^{2}} \\ &=\frac{9 \times 10^{9} \times 16 \times 10^{-9} \times \cos 60^{\circ}}{36 \times 10^{-2}} \\ &=\frac{9 \times 16}{36} \times 10^{2} \times \frac{1}{2} \\ &=200 \mathrm{V} \end{aligned}

Posted by

Ritika Harsh

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