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A solution is prepared by dissolving 2 g of NaOH  in 100 g of water. What is the molarity of the solution? (Given:\text { Molar mass of } \mathrm{NaOH}=40 \mathrm{~g} / \mathrm{mol} \text {. })

Option: 1

0.5 M


Option: 2

1 M


Option: 3

2 M


Option: 4

4 M


Answers (1)

best_answer

To calculate the molarity of the solution, we need to first calculate the number of moles of NaOH present in the solution.

\begin{aligned} & \text { Number of moles of } \mathrm{NaOH}=\text { Mass of } \mathrm{NaOH} / \text { Molar mass of } \mathrm{NaOH} \\ & =2 \mathrm{~g} / 40 \mathrm{~g} / \mathrm{mol} \\ & =0.05 \mathrm{~mol} \end{aligned}

Now, we need to calculate the volume of the solution in liters.

\begin{aligned} & \text { Volume of the solution }=\text { Mass of solvent } / \text { Density of solvent } \\ & =100 \mathrm{~g} / 1 \mathrm{~g} / \mathrm{mL} \\ & =100 \mathrm{~mL} \\ & =0.1 \mathrm{~L} \end{aligned}

Therefore, the molarity of the solution can be calculated as:

\begin{aligned} & \text { Molarity }=\text { Number of moles of solute/Volume of solution in liter } \\ & =0.05 \mathrm{~mol} / 0.1 \mathrm{~L} \\ & =0.5 \mathrm{M} \end{aligned}

Hence, the correct answer is option a) 0.5 M.

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Anam Khan

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