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  • A solution is prepared by dissolving a non-volatile solute in a solvent. Which of the following will result in a greater elevation in boiling point of the solution?<div class='qna-opt

A solution is prepared by dissolving a non-volatile solute in a solvent. Which of the following will result in a greater elevation in boiling point of the solution?

Option: 1

Dissolving 5 g of solute in 100 g of solvent.

 


Option: 2

Dissolving 5 g of solute in 200 g of solvent.


Option: 3

Dissolving 10 g of solute in 100 g of solvent.


Option: 4

Dissolving 10 g of solute in 200 g of solvent.


Answers (1)

best_answer

The elevation in boiling point of a solution is directly proportional to the number of solute particles in the solution, which is given by the van't Hoff factor, i. For a non-volatile solute, i = 1.

In options 1) and 2), the amount of solute is the same, but the amount of solvent is different. Therefore, the number of solute particles in the solution will be the same, and so will be the elevation in boiling point. Hence, options 1) and 2) can be eliminated.

In options 3) and 4), the amount of solvent is the same, but the amount of solute is different. Therefore, the number of solute particles in the solution will be different, and so will be the elevation in boiling point. The solution with a higher amount of solute will have more solute particles, and therefore a greater elevation in boiling point. Hence, option 4) is the correct answer.

Note that the molarity of the solutions is not given, and is not required to solve this problem.

Posted by

manish painkra

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