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A spring is compressed by 0.2 m, and it exerts a force of 10 N. What will be the force exerted by the spring if it is compressed by 0.4 m?

Option: 1

 10 N


Option: 2

20 N


Option: 3

40 N


Option: 4

80 N


Answers (1)

best_answer

The force exerted by a spring is given by Hooke's law, which states that the force F is directly proportional to the displacement x from its equilibrium position, and can be expressed as F = -kx, where k is the spring constant.

So, we can write:

F1 = -kx1 (where x1 = 0.2 m and F1 = 10 N)

F2 = -kx2 (where x2 = 0.4 m and we need to find F2)
 

Dividing the two equations, we get

\frac{F2}{F1}=\frac{x2}{x1}
F2=F1*\frac{x2}{x1}= 10*\frac{0.4}{0.2} = 20N

Posted by

Gaurav

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