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  • A square frame of side 10 cm and a long  straight wire carrying cu

A square frame of side 10 cm and a long  straight wire carrying current 1 A are in    the plane of the paper. Starting from close  to the wire, the frame moves towards the right with a constant speed of 10 ms-1 (see figure). The e.m.f induced  (in \mu V) at the time the    left arm of the frame is at x=10 cm from  the wire is :        

 

Option: 1

1


Option: 2

2


Option: 3

0.75


Option: 4

0.5


Answers (1)

In the given question, Current flowing through the wire, I = 1A Speed of the frame, v=10ms-1

Side of square loop, l=10cm

Distance of square frame from current carrying wires x = 10 cm. 

\text { According to Biot-Savart } \mathrm{law} \ \ \ B=\frac{\mu_{0}}{4 \pi} \frac{I d l \sin \theta}{x^{2}}

B=\frac{4 \pi \times 10^{-7}}{4 \pi} \times \frac{1 \times 10^{-1}}{\left(10^{-1}\right)^{2}} = 10^{-6}

\text { Induced e.m.f. } \mathrm{e}=\mathrm{Blv}=10^{-6} \times 10^{-1} \times 10

= 1\mu V 

Posted by

Sumit Saini

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