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A superconducting loop of radius R has self inductance L. A uniform & constant magnetic field B is applied perpendicular to the plane of the loop. Initially current in this loop is zero. The loop is rotated by 180º. The current in the loop after rotation is equal to        

Option: 1

zero


Option: 2

\frac{B\pi R^{2}}{L}


Option: 3

\frac{2B\pi R^{2}}{L}


Option: 4

\frac{B\pi R^{2}}{2L}


Answers (1)

best_answer

 

Co efficient of self induction -

\phi \, \alpha \, I\Rightarrow N\phi \, \alpha\: I

N\phi \,=L\, I

L=\frac{N\phi }{I}\,
 

- wherein

N\phi = Number of flux linkage with coil.

 

 

Flux can't change in a superconducting loop.                             \Delta \phi = 2\pi R^{2}. B

 Initially current was zero. So self flux was zero. 

Finally Li = 2\pi R^{2}\times B

i = \frac{2\pi R^{2}\times B}{L}

Posted by

Divya Prakash Singh

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