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  • A thermally insulated rigid container contains an ideal gas at . It is

A thermally insulated rigid container contains an ideal gas at 27^{\circ} \mathrm{C}. It is fitted with a heating coil of
resistance 50 Ω . A current is passed through the coil for 10 minutes by connecting it to a d. c. source of 10
V. The change in the internal energy is

Option: 1

Zero


Option: 2

300 J


Option: 3

600 J


Option: 4

1200 J


Answers (1)

best_answer

Heat produced is given by

\mathrm{d Q=\frac{V^2 t}{R}=\frac{(10)^2 \times(10 \times 60)}{50}=1200 \mathrm{~J}}

Since the container is rigid, the change in volume dV = 0. Hence work done dQ =
PdV = 0. From the first law of thermodynamics, the change in internal energy is dU =
dQ − dW = dQ = 1200 J

Posted by

Deependra Verma

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