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  • A volume contraction of 25 mL was observed when 30 mL mixture of <img alt="\mathrm{CO\; and\; H_{2}}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BCO%5C%3B%20and%

A volume contraction of 25 mL was observed when 30 mL mixture of \mathrm{CO\; and\; H_{2}}  was exploded & cooled with \mathrm{ O_{2}} in excess. It is given that all V measurements correspond to room temperature & pressure of 1 atm. Calculate volume ratio in the original \mathrm{CO\; and\; H_{2}} mixture.

Option: 1

1 : 2


Option: 2

1 : 5


Option: 3

2 : 1


Option: 4

3 : 1


Answers (1)

best_answer

\\\mathrm{CO}+\frac{1}{2} \mathrm{O}_2 \rightarrow \mathrm{CO}_2\\\; \; \; \text{x}\; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \text{x}

\underset{\textup{(30-x)}}{ \mathrm{H}_2}+\frac{1}{2} \mathrm{O}_2 \rightarrow \underset{\textup{30}}{\mathrm{H}_2 \mathrm{O}}

After cooling \mathrm{(30-x)mL} of \mathrm{H_{2}O}. Vapour liquifies k hence shrinks in volume.

 \mathrm{30-x=25}

\mathrm{x=5=volume\; of\; CO}

Hence volume of \mathrm{H_{2}}

              \begin{aligned} & =30-x \\ & =30-5=25 \end{aligned}

Ratio      = 5 : 25

               = 1 : 5

Posted by

vishal kumar

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