Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • A wire, suspended vertically from one end, is stretched by attaching a weight of to the l

A wire, suspended vertically from one end, is stretched by attaching a weight of 20 \mathrm{~N} to the lower end. The weight stretches the wire by 1 \mathrm{~mm}. How much energy is gained by the wire?

Option: 1

0.01 J


Option: 2

0.02 J


Option: 3

0.04 J


Option: 4

1.0 J


Answers (1)

best_answer

We have seen above that work done by a force $F$ to produce an extension l in the wire \mathrm{=\frac{1}{2} F \times l}. Thus, the energy gained by the wire

\mathrm{=\frac{1}{2} F \times l=\frac{1}{2} \times 20 \times \left(1 \times 10^{-3}\right)=10^{-2} \mathrm{~J}=0.01 \mathrm{~J}}.

Hence the correct choice is (a).

Posted by

Suraj Bhandari

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET MBBS cut-off rises for Bangalore Medical College, drops for other Karnataka govt colleges
anam-khan

Aiming for 650+ in NEET 2025? Focus on these high-weightage chapters
anam-khan

Sri Chaitanya Academy, Infinity Learn launch NEET preparation course, 'ATREYA'

Latest Question