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  • An engine pumps water continuously through a hose. Water leaves the hose with a velocity v and m is the mass per unit length of the water jet. What is the rate at

An engine pumps water continuously through a hose. Water leaves the hose with a velocity v and m is the mass per unit length of the water jet. What is the rate at which kinetic energy is imparted to water?

Option: 1

mv2


Option: 2

\frac{1}{2}\text{mv}^{2}


Option: 3

\frac{1}{2}\text{m}^{2}\text{v}^{2}


Option: 4

\frac{1}{2}\text{mv}^{3}


Answers (1)

best_answer

Rate of kinetic energy= \frac{d(K E)}{dt}=\frac{d( \frac{1}{2} M v^{2})}{d t}
But $\quad M=m L$
So \frac{d(K E)}{dt}=\frac{1}{2} \frac{d (mL v^{2})}{d t} =\frac{1}{2} m v^{3}$

Posted by

Ritika Jonwal

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